document.write( "Question 42582: Find the equation of the line through the given point that is perpendicular to the given line. y=-2/3x+7, R(4,-1) \n" ); document.write( "
Algebra.Com's Answer #27676 by jmg(22)\"\" \"About 
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In the equation y = -2/3x + 7 , I am assuming the x is not on the bottom with the 3 ??????? If it is you can't work this problem in this manner. As long as the problem is (2/3)x, this is how you work it. \r
\n" ); document.write( "\n" ); document.write( "In the given equation the slope is the number in front of x. So the slope is
\n" ); document.write( "-2/3.
\n" ); document.write( "A line perpendicular to that line would have the negative reciprocal slope.\r
\n" ); document.write( "\n" ); document.write( "So the slope of the perpendicular line would be 3/2 (flip it and change the sign to the opposite)\r
\n" ); document.write( "\n" ); document.write( "Then you fill into point-slope form: \r
\n" ); document.write( "\n" ); document.write( "y - y sub 1 = m (x - x sub 1), where m is the slope and x sub 1 and y sub 1 are the coordinates of point R(4, -1) {{ sub means subscript by the way}}
\n" ); document.write( "Fill in the formula
\n" ); document.write( "y - (-1) = 3/2 (x - 4)
\n" ); document.write( "y + 1 = (3/2)x - 6
\n" ); document.write( "y = (3/2)x - 7 \r
\n" ); document.write( "\n" ); document.write( "This is the answer in slope-intercept form. You did not specify what form to write it in! \r
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