document.write( "Question 42556: Use the Binomial Theorem to find the sixth term in the expansion of (m+2p)^7.\r
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Algebra.Com's Answer #27670 by psbhowmick(878)\"\" \"About 
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The r-th term in the binomial expansion of \"%28a+%2B+x%29%5En\" for positive integral values of 'n' is given by \"t%5Br%5D+=+nC%5Br%5D%2Aa%5E%28n-r%29%2Ax%5Er\".\r
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\n" ); document.write( "\n" ); document.write( "Here, a = m, x = 2p, n = 7.
\n" ); document.write( "For the 6th term, r = 6.
\n" ); document.write( "So replace a, x, n and r in the formula of r-th term and get
\n" ); document.write( "\"t%5B6%5D+=+7C%5B6%5D%2Am%5E%287-6%29%2A%282a%29%5E6\"
\n" ); document.write( "or \"t%5B6%5D+=+2%5E6%2A7C%5B6%5D%2Am%5E1a%5E6\"\r
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\n" ); document.write( "\n" ); document.write( "Now, \"7C%5B6%5D+=+7%21%2F%286%21%287-6%29%21%29\" = \"7%21%2F%286%211%21%29\" = \"%286%21%2A7%29%2F%286%21%2A1%29\" = 7.\r
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\n" ); document.write( "\n" ); document.write( "Hence the reqd 6th term is \"t%5B6%5D+=+2%5E6%2A7%2Ama%5E6\" = \"64%2A7%2Ama%5E6\" = \"448ma%5E6\".
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