document.write( "Question 390281: graph f(x)=-x^2+4x-3, labeling the y-intercept, vertex, and axis of symmetry\r
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Algebra.Com's Answer #276675 by ewatrrr(24785)\"\" \"About 
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\n" ); document.write( "f(x)=-x^2+4x-3
\n" ); document.write( "y-intercept when x = 0 Pt(0-3)
\n" ); document.write( "x-intercept when y = 0
\n" ); document.write( "y = -x^2 + 4x - 3 = 0 Completing Square to put into vertex form
\n" ); document.write( "y = -[x^2 - 4x] - 3 = 0
\n" ); document.write( "y = -[(x-2)^2 - 4] - 3 = 0
\n" ); document.write( "y = -(x-2)^2 + 4 - 3 = 0 Vertex Pt (2,1) axis of symmetry is x = 2
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