document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=42427>Question 42427</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The Randolphs used 12 more gal of fuel oil in October<BR>\n" );
document.write( "than in September and twice as much oil in November as in September. If they<BR>\n" );
document.write( "used 132 gal for the 3 months, how much was used during each month? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #27666 by </B><A HREF=/tutors/aboutme.mpl?userid=Socom491><B>Socom491(19)</B></A><img src=\"/images/stars/stars-06.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Socom491><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=27666\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Ok to solve this, we first have to set up our variables.\r<BR>\n" );
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document.write( "Let n= The amount of oil used in September<BR>\n" );
document.write( "Let n+12= Amount of Oil used in October<BR>\n" );
document.write( "Let 2n= Amount of oil used in November\r<BR>\n" );
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document.write( "So now we have to add everything up and have it total 132 gallons of gas, because that's how much they used.\r<BR>\n" );
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document.write( "n+n+12+2n= 132\r<BR>\n" );
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document.write( "Now we combine like terms, and solve for n.\r<BR>\n" );
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document.write( "4n+12=132<BR>\n" );
document.write( "  -12=-12<BR>\n" );
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document.write( "4n=120<BR>\n" );
document.write( "/4= /4\r<BR>\n" );
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document.write( "n=30\r<BR>\n" );
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document.write( "Ok so we now know that n=30, now we can plug thirty for n and figure out how much oil they used for each month.\r<BR>\n" );
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document.write( "20= September<BR>\n" );
document.write( "32= October<BR>\n" );
document.write( "40= November\r<BR>\n" );
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document.write( " </SPAN>\n" );
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