document.write( "Question 390238: two towns are 780 kms apart .two superfast trains leave from both the townsat 3 pm towards each other at the speed of 120 and 140 km/hr each.at what time will the trains pass each other \n" ); document.write( "

Algebra.Com's Answer #276659 by josmiceli(19441) $\"\"$ $\"About$

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You can think of one train as standing still
\n" ); document.write( "and the other train moving at the sum of
\n" ); document.write( "their speeds
\n" ); document.write( "The formula for the moving train is
\n" ); document.write( " $\"d+=+r%2At\"$
\n" ); document.write( " $\"d+=+780\"$ km
\n" ); document.write( " $\"r+=+120+%2B+140\"$
\n" ); document.write( " $\"r+=+260\"$
\n" ); document.write( " $\"780+=++260%2At\"$
\n" ); document.write( " $\"t+=+3\"$ hrs
\n" ); document.write( "The trains will pass at 3 PM + 3 hrs, or 6 pm
\n" ); document.write( "You can also check answer this way:
\n" ); document.write( "slower train:
\n" ); document.write( " $\"d%5B1%5D+=+r%2At\"$
\n" ); document.write( " $\"d%5B1%5D+=+120%2A3\"$
\n" ); document.write( " $\"d%5B1%5D+=+360\"$ km
\n" ); document.write( "faster train:
\n" ); document.write( " $\"d%5B2%5D+=+140%2A3\"$
\n" ); document.write( " $\"d%5B2%5D+=+420\"$
\n" ); document.write( " $\"d%5B1%5D+%2B+d%5B2%5D+=+360+%2B+420\"$
\n" ); document.write( " $\"d%5B1%5D+%2B+d%5B2%5D+=+780\"$ km
\n" ); document.write( "OK \n" ); document.write( "

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