document.write( "Question 390193: A man standing on top of a building sees an automobile on a street below him.The angle of depression is 26degrees 22'.If his eye is 550 ft above the level of the automoile, how far is the automobile for him.\r
\n" ); document.write( "\n" ); document.write( "(Can you please explain in details how the answer is found.)
\n" ); document.write( "thank you !
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Algebra.Com's Answer #276635 by mananth(16946)\"\" \"About 
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A man standing on top of a building sees an automobile on a street below him.The angle of depression is 26degrees 22'.If his eye is 550 ft above the level of the automoile, how far is the automobile for him.
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\n" ); document.write( "draw a sketch
\n" ); document.write( "a rectangle ABCD
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\n" ); document.write( "A man
\n" ); document.write( "B vertical point below the man
\n" ); document.write( "C= car position
\n" ); document.write( "D = vertical position above car in line with A
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\n" ); document.write( "We have to find length AC.
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\n" ); document.write( "angle DAC = angle of depression = 26deg.22'
\n" ); document.write( "this is = angle ACB . alternate angles
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\n" ); document.write( "sine angle ACB = vertical / hypotenuse (AC)
\n" ); document.write( "sine 26 degrees 22 minutes = 550/AC
\n" ); document.write( "AC = 550/sine 26 degrees 22 minutes
\n" ); document.write( "AC = 1238 feet
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\n" ); document.write( "m.ananth@hotmail.ca\r
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