document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=390191>Question 390191</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The sum of 4 times joans age and 3 times jim's age is 47. Jim is 1 yea<BR>\n" );
document.write( "r less than twice as old as joan. Find each of their ages. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #276609 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=276609\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The sum of 4 times joans age and 3 times jim's age is 47. Jim is 1 yea<BR>\n" );
document.write( "r less than twice as old as joan. Find each of their ages.<BR>\n" );
document.write( "...<BR>\n" );
document.write( "Joan x years<BR>\n" );
document.write( "Jim 2x-1<BR>\n" );
document.write( "..<BR>\n" );
document.write( "4 times joan's age = 4x<BR>\n" );
document.write( "3 times jim's age = 3(2x-1)<BR>\n" );
document.write( "..<BR>\n" );
document.write( "4x+3(2x-1)=47<BR>\n" );
document.write( "4x+6x-3=47<BR>\n" );
document.write( "10x-3=47<BR>\n" );
document.write( "add 3 to both sides<BR>\n" );
document.write( "10x=50<BR>\n" );
document.write( "/10<BR>\n" );
document.write( "x=5 Joan's age<BR>\n" );
document.write( "Jim's age = 2x-1=2*5-1=9 <BR>\n" );
document.write( "Joan 5 years<BR>\n" );
document.write( "Jim 9 years<BR>\n" );
document.write( "..<BR>\n" );
document.write( "m.ananth@hotmail.ca </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );