document.write( "Question 390118: i need help in solving log(base 3)x+log(base 3)(2x)-log(base 3)(x+3)=1 \n" ); document.write( "
Algebra.Com's Answer #276571 by Alan3354(69443)\"\" \"About 
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log(base 3)x+log(base 3)(2x)-log(base 3)(x+3)=1
\n" ); document.write( "\"log%283%2Cx%29+%2B+log%283%2C2x%29+-+log%283%2C%28x%2B3%29%29+=+1\"
\n" ); document.write( "\"log%283%2C%28x%2A2x%2F%28x%2B3%29%29%29+=+1\"
\n" ); document.write( "x*2x/(x+3) = 3
\n" ); document.write( "\"2x%5E2+=+3x+%2B+9\"
\n" ); document.write( "\"2x%5E2+-+3x+-+9+=+0\"
\n" ); document.write( "(2x + 3)(x - 3) = 0
\n" ); document.write( "x = 3
\n" ); document.write( "---------
\n" ); document.write( "x = -3/2 *** has to be rejected since you can't take a log of a negative number.
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