document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=390112>Question 390112</A>: <I><SPAN STYLE=\"word-break: break-all;\"> I cannot figure out how to set up this problem... I created a chart with the information, but just don't feel like I have enough to solve! Can you help? \r<BR>\n" );
document.write( "\n" );
document.write( "Airplane A travels 2800 km at a certain speed. Airplane B travels 2000 km at a speed that is 50 km/h faster than Plane A in 3 hours less time. Find the speed of each.  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #276564 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=276564\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Airplane A travels 2800 km at a certain speed. Airplane B travels 2000 km at a speed that is 50 km/h faster than Plane A in 3 hours less time. Find the speed of each. <BR>\n" );
document.write( "...<BR>\n" );
document.write( "Airplane A travels 2800 km at x mph<BR>\n" );
document.write( "Airplane B travels 2000 km at x+50  mph<BR>\n" );
document.write( " ...<BR>\n" );
document.write( "Time plane A - time plane B = 3 hours<BR>\n" );
document.write( "...<BR>\n" );
document.write( "t=d/r<BR>\n" );
document.write( "..<BR>\n" );
document.write( "2800/x - 2000/(x+50)=3<BR>\n" );
document.write( "LCD = x(x+50)<BR>\n" );
document.write( "(2800(x+50)-2000x)/x(x+50)=3<BR>\n" );
document.write( "2800x+140000=2000x = 3x(x+50)<BR>\n" );
document.write( "800x+140000=3x^2+150x<BR>\n" );
document.write( "3x^2-650x-140000=0<BR>\n" );
document.write( "3x^2-1050x+400x-140000=0<BR>\n" );
document.write( "3x(x-350)+400(x-350)=0<BR>\n" );
document.write( "(x-350)(3x+400)=0<BR>\n" );
document.write( "x = 350 mph the speed of plane A<BR>\n" );
document.write( "speed of plane B = 350 +50 = 400 mph<BR>\n" );
document.write( "...<BR>\n" );
document.write( "m.ananth@hotmail.ca </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );