document.write( "Question 390066: how do you write a quadratic equation with a root of 2-5i ? \n" ); document.write( "
Algebra.Com's Answer #276521 by robertb(5830)\"\" \"About 
You can put this solution on YOUR website!
\"%28x-%282-5i%29%29%28x+-+%282%2B5i%29%29+=+%28%28x-2%29%2B5i%29%28%28x+-+2%29-5i%29%29\"
\n" ); document.write( " = \"%28x-2%29%5E2+-+25i%5E2+=+x%5E2+-+4x+%2B+4+%2B+25+=+x%5E2+-+4x+%2B+29+=+0\".
\n" ); document.write( "Thus any quadratic equation \"a%28x%5E2+-+4x+%2B+29%29+=+0\", where a is not equal to 0, will have 2 - 51 as root.
\n" ); document.write( "(Note that if A + Bi is a root of the quadratic equation, then so is its conjugate A - Bi.)
\n" ); document.write( "
\n" );