document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=390071>Question 390071</A>: <I><SPAN STYLE=\"word-break: break-all;\"> If one root of the equation ... 2x^2+10x+k=0 is -2, find K and the other root? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #276516 by </B><A HREF=/tutors/aboutme.mpl?userid=robertb><B>robertb(5830)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=robertb><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=robertb><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=276516\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Put x = -2 into the equation:  <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=2%2A%28-2%29%5E2+%2B+10%2A-2+%2B+k+=+0 ALIGN=MIDDLE  ALT=\"2%2A%28-2%29%5E2+%2B+10%2A-2+%2B+k+=+0\"   DISABLED_style= \"max-width:90%; height:auto;\" > ====> 8 - 20 + k = 0, or -12 + k = 0, or k = 12.  The equation is then <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=2x%5E2+%2B+10x+%2B+12+=+0 ALIGN=MIDDLE  ALT=\"2x%5E2+%2B+10x+%2B+12+=+0\"   DISABLED_style= \"max-width:90%; height:auto;\" >.  The equation simplifies to <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=x%5E2+%2B+5x+%2B+6+=+0 ALIGN=MIDDLE  ALT=\"x%5E2+%2B+5x+%2B+6+=+0\"   DISABLED_style= \"max-width:90%; height:auto;\" >, which is the same as (x + 2)(x+3)=  0, so the other root is -3. </SPAN>\n" );
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