document.write( "Question 390059: find the second of the three consecutive positive even integers such that the product of the first and second is 64 less than the square of the third \n" ); document.write( "

Algebra.Com's Answer #276506 by ewatrrr(24785) $\"\"$ $\"About$

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document.write( "Hi,        
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document.write( "Let x, (x+2),(x+4) represent the three consecutive positive even integers
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document.write( "Question States***
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document.write( " x(x+2) = (x+4)^2 - 64
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document.write( "solving for x
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document.write( " x^2 + 2x = x^2 + 8x + 16 - 64
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document.write( "       48 = 6x
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document.write( "        x = 8, the first of the three.  The Second Integer is 10\r
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document.write( "CHECKING our Answer*****
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document.write( " 8*10 = 144 - 64 \n" );
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