document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=5353>Question 5353</A>: <I><SPAN STYLE=\"word-break: break-all;\"> I need to solve by factoring:  m^2-2m-63=0\r<BR>\n" );
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document.write( "Thanks for your help. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #2765 by </B><A HREF=/tutors/aboutme.mpl?userid=guapa><B>guapa(62)</B></A><img src=\"/images/stars/stars-08.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=guapa><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=2765\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> m²- 2m - 63 = 0<BR>\n" );
document.write( "You need to find 2 numbers whose sum is -2 and whose product is -63. A way to do that is to express 63 in its prime factors. 3*3*7. Now use these factors in different combination and you´ll find the 2 numbers you need. In this case the numbers are 9 (3*3) and 7(7). So, -9+7= -2 and -9*7= -63.<BR>\n" );
document.write( "Now you can solve the equation as follows:<BR>\n" );
document.write( "m²-9m +7m -63=0 Now you need to factor<BR>\n" );
document.write( "m(m-9)+7(m-9)=0<BR>\n" );
document.write( "(m-9)(m+7)=0<BR>\n" );
document.write( "m-9=0, m=9<BR>\n" );
document.write( "m+7=0, m= -7<BR>\n" );
document.write( "The solution set is {-7,9}<BR>\n" );
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