document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=389881>Question 389881</A>: <I><SPAN STYLE=\"word-break: break-all;\"> (sqare root 3) + 1 / (square root 3) - 1 would be equal to:<BR>\n" );
document.write( "-1<BR>\n" );
document.write( "2<BR>\n" );
document.write( "2 + square root 3<BR>\n" );
document.write( "5 + square root 3 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #276405 by </B><A HREF=/tutors/aboutme.mpl?userid=edjones><B>edjones(8007)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=edjones><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=edjones><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=276405\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> sqrt(3)+1/sqrt(3)-1 * sqrt(3)+1/sqrt(3)+1 Rationalizing the denominator.<BR>\n" );
document.write( "=(4+2sqrt(3))/2<BR>\n" );
document.write( "=2+sqrt(3)<BR>\n" );
document.write( ".<BR>\n" );
document.write( "Ed </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );