document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=389833>Question 389833</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A rectangle garden is to be fenced along three sides with 70 meters of fencing material. Find the dimensions of the garden if the area is to be 600m^2 (Show Your Solution) </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #276367 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=276367\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> <BR>\n" );
document.write( "Only three sides fencing.<BR>\n" );
document.write( "l+2w=70<BR>\n" );
document.write( "2w=70-l<BR>\n" );
document.write( "w=(70-l)/2<BR>\n" );
document.write( "...<BR>\n" );
document.write( "Area = l*w<BR>\n" );
document.write( "Area = l*(70-l)/2<BR>\n" );
document.write( "600=(70l-l^2)/2<BR>\n" );
document.write( "1200 = 70l -l^2<BR>\n" );
document.write( "l^2-70l+1200=0<BR>\n" );
document.write( "l^2-40l-30l+1200=0<BR>\n" );
document.write( "l(l-40)-30(l-40)=0<BR>\n" );
document.write( "(l-30)(l-40)<BR>\n" );
document.write( "l= 30 OR 40<BR>\n" );
document.write( "...<BR>\n" );
document.write( "l=30 w= 20<BR>\n" );
document.write( "l=40 w=15<BR>\n" );
document.write( "The dimensions can be 30 by 20 OR 40 by 15 meters<BR>\n" );
document.write( "...<BR>\n" );
document.write( "m.ananth@hotmail.ca </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );