document.write( "Question 389754: -x^2+y^2+4x-13=0
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document.write( "classify each conic section and sketch it on a graph \n" );
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Algebra.Com's Answer #276365 by lwsshak3(11628)![]() ![]() ![]() You can put this solution on YOUR website! -x^2+y^2+4x-13=0 \n" ); document.write( "complete the square. \n" ); document.write( "-(x^2+4x+4) +y^2=13-4 \n" ); document.write( "-(x+2)^2+y^2 = 9 \n" ); document.write( "y^2/9-(x+2)^2/9 =1 \n" ); document.write( "standard form of parabola, (x-h)^2/a^2-(y-k)^2/b^2 = 1 (opens horizontally) \n" ); document.write( "or (y-k)^2/a^2-(x-h)^2/b^2 = 1 (opens vertically) \n" ); document.write( "this is a hyperbola opening in the vertical direction \n" ); document.write( "Other parameters: \n" ); document.write( "a^2=9 \n" ); document.write( "a=3 \n" ); document.write( "b^2=9 \n" ); document.write( "b=3 \n" ); document.write( "c=sqrt a^2+b^2=sqrt 18 =4.24 \n" ); document.write( "ctr((-2,0) \n" ); document.write( "foci (-2,±c) \n" ); document.write( "foci (-2,±4.24) \n" ); document.write( "vertex (-2,±a) \n" ); document.write( "vertex (-2,±3) \n" ); document.write( "asymptotes y=±(a/b)x=(3/3)x=x\r \n" ); document.write( "\n" ); document.write( "sorry I don't have ways to draw the hyperbola here, but you should be able to do it with the above information. \n" ); document.write( " |