document.write( "Question 389825: on January 1, Mr. Warner and his son jointly invest a sum of money at an annual rate of 6.75%. On January 1 of the following year, their total investment is worth $5978. If Mr. Warner invested $4500 of his own money, how much money did his son invest?\r
\n" ); document.write( "\n" ); document.write( "I know the answer is $1100 but I don't know why it's $1100???\r
\n" ); document.write( "\n" ); document.write( "Thanks.
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Algebra.Com's Answer #276358 by josmiceli(19441)\"\" \"About 
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Let \"x\" = amount his son invested
\n" ); document.write( "given:
\n" ); document.write( "Mr Warner invested \"4500\"
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\n" ); document.write( "After 1 year,
\n" ); document.write( "\"4500+%2B+x+%2B+.0675%2A%284500+%2B+x%29+=+5978\"
\n" ); document.write( "\"4500+%2B+x+%2B+303.75+%2B+.0675x+=+5978\"
\n" ); document.write( "\"1.0675x+=+5978+-+4500+-+303.75\"
\n" ); document.write( "\"1.0675x+=+5978+-+4803.75\"
\n" ); document.write( "\"1.0675x+=+1174.25\"
\n" ); document.write( "\"x+=+1100\"
\n" ); document.write( "His son invested $1,100
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