document.write( "Question 42524: The length of a rectangle is 2 cm more than twice its width. If the perimeter of the rectangle is 52 cm, find the dimensions of the rectangle.\r
\n" ); document.write( "\n" ); document.write( "let the width of the rectangle is x cm
\n" ); document.write( "then length of the rectangle will be 2x+2
\n" ); document.write( "given perimeter of the rectangle is 52 cm
\n" ); document.write( "=>2*(x+(2x+2))=52
\n" ); document.write( "=>2*(3x+2)=52
\n" ); document.write( "=>3x+2=26
\n" ); document.write( "=>3x=24
\n" ); document.write( "=>x=8
\n" ); document.write( "hence lenghth of the rectangle is 18cm and width is 8cm
\n" ); document.write( "

Algebra.Com's Answer #27634 by Nate(3500)\"\" \"About 
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width = w
\n" ); document.write( "length = 2w + 2
\n" ); document.write( "\"2l+%2B+2w+=+p\"
\n" ); document.write( "\"2%282w+%2B+2%29+%2B+2%28w%29+=+52\"
\n" ); document.write( "\"4w+%2B+4+%2B+2w+=+52\"
\n" ); document.write( "\"6w+=+48\"
\n" ); document.write( "\"w+=+8\"
\n" ); document.write( "width = 8
\n" ); document.write( "length = 2w + 2 = 2(8) + 2 = 18
\n" ); document.write( "
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