document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=389766>Question 389766</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A garden measuring 12 meters by 16 meters is to have a pedestrian pathway installed around it, increasing the total area to 285 square meters. What will be the width of the pathway? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #276307 by </B><A HREF=/tutors/aboutme.mpl?userid=scott8148><B>scott8148(6628)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=scott8148><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=scott8148><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=276307\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> (2w + 12)(2w + 16) = 285\r<BR>\n" );
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document.write( "4w^2 + 56w + 192 = 285 ___ 4w^2 + 56w - 93 = 0\r<BR>\n" );
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document.write( "factoring ___ (2w + 31)(2w - 3) = 0\r<BR>\n" );
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document.write( "2w + 31 = 0 ___ 2w = -31 ___ w = -31/2 ___ negative value not realistic\r<BR>\n" );
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document.write( "2w - 3 = 0 ___ 2w = 3 ___ w = 3/2 </SPAN>\n" );
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