document.write( "Question 389775: if you had $36000 compound 5% per year then compounded it 35 years, what would it be? \n" ); document.write( "
Algebra.Com's Answer #276301 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
I'm assuming you're compounding once a year.\r
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\n" ); document.write( "\n" ); document.write( "Recall that the compound interest formula is\r
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\n" ); document.write( "\n" ); document.write( "\"A=P%281%2Br%2Fn%29%5E%28n%2At%29\"\r
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\n" ); document.write( "\n" ); document.write( "where A is the return, P is the principal (ie amount invested), r is the interest rate (in decimal form), n is the compounding frequency (per year), and t is the time in years.\r
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\n" ); document.write( "\n" ); document.write( "\"A=P%281%2Br%2Fn%29%5E%28n%2At%29\" Start with the compound interest formula\r
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\n" ); document.write( "\n" ); document.write( "\"A=36000%281%2B0.05%2F1%29%5E%281%2A36%29\" Plug in \"P=36000\", \"r=0.05\" (the decimal equivalent of 5%), \"n=1\" and \"t=36\".\r
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\n" ); document.write( "\n" ); document.write( "\"A=36000%281%2B0.05%29%5E%281%2A36%29\" Evaluate \"0.05%2F1\"} to get \"0.05\"\r
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\n" ); document.write( "\n" ); document.write( "\"A=36000%281.05%29%5E%281%2A36%29\" Add \"1\" to \"0.05\" to get \"1.05\"\r
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\n" ); document.write( "\n" ); document.write( "\"A=36000%281.05%29%5E%2836%29\" Multiply \"1\" and \"36\" to get \"36\".\r
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\n" ); document.write( "\n" ); document.write( "\"A=36000%285.79181613597187%29\" Evaluate \"%281.05%29%5E%2836%29\" to get \"5.79181613597187\".\r
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\n" ); document.write( "\n" ); document.write( "\"A=208505.380894987\" Multiply \"36000\" and \"5.79181613597187\" to get \"208505.380894987\".\r
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\n" ); document.write( "\n" ); document.write( "\"A=208505.38\" Round to the nearest hundredth (ie to the nearest penny).\r
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\n" ); document.write( "\n" ); document.write( "So after 36 years, you would have about $208,505.38 in the account.
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