document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=389692>Question 389692</A>: <I><SPAN STYLE=\"word-break: break-all;\"> log9 (4p2 - 7p + 53) = log3 (4p-3) </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #276292 by </B><A HREF=/tutors/aboutme.mpl?userid=lwsshak3><B>lwsshak3(11628)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=lwsshak3><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=276292\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The approach here is to change the base 9 logarithm to a base 3 logarithm, using the change of base formula<BR>\n" );
document.write( "log9 (4p2 - 7p + 53) = log3 (4p-3)<BR>\n" );
document.write( "changing the left term to a base 3 logarithm,\r<BR>\n" );
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document.write( "log3 (4p2 - 7p + 53)/log3(9)<BR>\n" );
document.write( "log3(9)=2<BR>\n" );
document.write( "log3 (4p2 - 7p + 53)/2= log3 (4p-3)\r<BR>\n" );
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document.write( "(4p2 - 7p + 53)/2=(4p-3)<BR>\n" );
document.write( "4p^2-7p+53=8p-6<BR>\n" );
document.write( "4p^2-15P+59=0\r<BR>\n" );
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document.write( "solve using the following quadratic equation, with a=4, b=-15, and c=59<BR>\n" );
document.write( "since the discriminate is negative, b^2-4*a*c =225-4*4*59=-719<BR>\n" );
document.write( "there is no solution<BR>\n" );
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