document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=389728>Question 389728</A>: <I><SPAN STYLE=\"word-break: break-all;\"> consider the sequence 1, 2/3,3/5,4/7,5/9,...    describe the pattern formed in the sequence, find the next 3 terms. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #276264 by </B><A HREF=/tutors/aboutme.mpl?userid=richard1234><B>richard1234(7193)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=richard1234><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=richard1234><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=276264\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The numerator increases by 1 for each successive term and the denominator increases by 2 (rewrite 1 as 1/1). Therefore,\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=a%5Bi%5D+=+i%2F%282i+-+1%29 ALIGN=MIDDLE  ALT=\"a%5Bi%5D+=+i%2F%282i+-+1%29\"   DISABLED_style= \"max-width:90%; height:auto;\" > where a[1] = 1.\r<BR>\n" );
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document.write( "The next three terms a_6, a_7, a_8 are 6/11, 7/13, 8/15 respectively. </SPAN>\n" );
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