document.write( "Question 389727: word problem. please use a table and the 5 step method to solve this problem. thank you.\r
\n" ); document.write( "\n" ); document.write( "marcus invested a sum of money at 5%. he invested an amount of money $250 more than the first amount at 6%. if the annual income from both investments totaled $59, how much did he invest at each rate. \n" ); document.write( "

Algebra.Com's Answer #276256 by ewatrrr(24785) $\"\"$ $\"About$

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document.write( "Hi,         
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document.write( "Let x represent the first amount invested at 5%
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document.write( "Therefore, (x+ $250) would be the amount invested at 6%
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document.write( "question States***
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document.write( " .05x + .06(x + $250) = $59
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document.write( "solving for x
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document.write( " .05x + .06x + .06*$250 = %59
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document.write( "     .11x = $59 - .06*$250
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document.write( "     .11x = $59 - $15
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document.write( "     .11x = $44
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document.write( "        x = $44/.11 = $400, amount invested at 5%
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document.write( "the amount invested at 6% would be $650   ($400+ $250)\r
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document.write( "IV. CHECKING Our Answer***
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document.write( " .05*$400 + .06*$650 = $20 + $39 = $59 \n" );
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