document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=389693>Question 389693</A>: <I><SPAN STYLE=\"word-break: break-all;\"> (please show the steps to how the rest of the problems were solved)<BR>\n" );
document.write( "Using exact values, find the value of:\r<BR>\n" );
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document.write( "A.12sin 30 degree - 6 tan 45 degree + sec 45 degrees/ 52 <BR>\n" );
document.write( "12·1/2 -6· 1 + &#8730;2/52 = &#8730;2/52\r<BR>\n" );
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document.write( "B.Sin2A + tan3A/2 - cos A + sec(a+ 15)<BR>\n" );
document.write( "Sin2A + tan3A/2 - cos A + sec(a+ 15)=  &#8730;3/2 + 1 - &#8730;3/2 + &#8730;2 = 1+&#8730;2\r<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #276233 by </B><A HREF=/tutors/aboutme.mpl?userid=Alan3354><B>Alan3354(69443)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Alan3354><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Alan3354><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=276233\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Using exact values, find the value of: <BR>\n" );
document.write( "A.12sin 30 degree - 6 tan 45 degree + sec 45 degrees/ 52 <BR>\n" );
document.write( "12*1/2 - 6*1 + &#8730;2/52 = &#8730;2/52<BR>\n" );
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document.write( "B. Sin2A + tan3A/2 - cos A + sec(a+ 15)<BR>\n" );
document.write( "Is it tan(3A/2), or (tan(A/2))^3 ?<BR>\n" );
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document.write( "Sin2A + tan3A/2 - cos A + sec(a+ 15)= &#8730;3/2 + 1 - &#8730;3/2 + &#8730;2 = 1+&#8730;2 <BR>\n" );
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