document.write( "Question 389690: Without graphing, find the domain of the following functions:\r
\n" ); document.write( "\n" ); document.write( "a)\"f%28x%29+=+sqrt%28%28x+-+3%29%2F%282x%5E2+-+8%29%29\", and\r
\n" ); document.write( "\n" ); document.write( "b)\"f%28x%29+=+root%283%2C%28x+%2B+5%29%2F%28x%5E2+-+9%29%29\".
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Algebra.Com's Answer #276219 by josmiceli(19441)\"\" \"About 
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a)\"f%28x%29+=+sqrt%28%28x+-+3%29%2F%282x%5E2+-+8%29%29\"
\n" ); document.write( "\"f%28x%29+=+sqrt%28x+-+3%29%2Fsqrt%282x%5E2+-+8%29%29\"
\n" ); document.write( "if \"x+=+3\"
\n" ); document.write( "The numerator is \"0\" and the denominator is (+)
\n" ); document.write( "and
\n" ); document.write( "If \"x+%3C+3\", The numerator is imaginary
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\n" ); document.write( "If \"x+%3E+3\", numerator is (+)
\n" ); document.write( "and denominator is (+)
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\n" ); document.write( "If \"x+=+2\"
\n" ); document.write( "The denominator is \"0\"
\n" ); document.write( "and the numerator is imaginary
\n" ); document.write( "If \"x+%3C+2\", the denominator is imaginary
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\n" ); document.write( "The restriction \"x+%3E+=+3\" includes
\n" ); document.write( "the restriction \"x+%3E+2\", so that is the domain
\n" ); document.write( "\"x+%3E=+3\" answer\r
\n" ); document.write( "\n" ); document.write( "b) \"f%28x%29+=+root%283%2C%28x+%2B+5%29%2F%28x%5E2+-+9%29%29\".
\n" ); document.write( "\"f%28x%29+=+root%283%2C%28x+%2B+5%29%29%2Froot%283%2C%28x%5E2+-+9%29%29\"
\n" ); document.write( "If \"x+=+-5\" the numerator is \"0\"
\n" ); document.write( "and the denominator is (+)
\n" ); document.write( "If \"x+%3C+-5\" the numerator is (-)
\n" ); document.write( "and the denominator is (+)
\n" ); document.write( "If \"x+%3E+-5\" the numerator is (-)
\n" ); document.write( "and the denominator is (+) or (-)
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\n" ); document.write( "If \"x+=+3\", the denominator is \"0\"
\n" ); document.write( "If \"x+%3C+3\" or \"x+%3E+3\" denominator is (+)
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\n" ); document.write( "\"x+=+3\" not allowed is the only restriction
\n" ); document.write( "The domain is \"x+%3E+3\" and \"x+%3C+3\"\r
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