document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=389536>Question 389536</A>: <I><SPAN STYLE=\"word-break: break-all;\"> 1.<BR>\n" );
document.write( "If A=<BR>\n" );
document.write( "[2 -4]<BR>\n" );
document.write( "[-2 5]<BR>\n" );
document.write( "FIND A^-1\r<BR>\n" );
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document.write( "2.<BR>\n" );
document.write( "use the question & answer above to calculate A X A^-1 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #276183 by </B><A HREF=/tutors/aboutme.mpl?userid=haileytucki><B>haileytucki(390)</B></A><img src=\"/images/stars/stars-10.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=haileytucki><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=haileytucki><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=276183\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> M[2,-4:-2,5]\r<BR>\n" );
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document.write( "These are both valid notations for the determinant of a matrix.<BR>\n" );
document.write( "detM[2,-4:-2,5]=M[D,2,-4:-2,5]\r<BR>\n" );
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document.write( "The determinant of a 2x2 matrix can be found using the formula M[D,a,b:c,d]=ad-cb<BR>\n" );
document.write( "detM[2,-4:-2,5]=(2)(5)-(-2)(-4)\r<BR>\n" );
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document.write( "Simplify the determinant.<BR>\n" );
document.write( "detM[2,-4:-2,5]=2\r<BR>\n" );
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document.write( "The determinant of M[2,-4:-2,5] is 2.<BR>\n" );
document.write( "2\r<BR>\n" );
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document.write( " Now, just plug in the 2 to the next question;\r<BR>\n" );
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document.write( "2^(-1)\r<BR>\n" );
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document.write( "Remove the negative exponent by rewriting 2^(-1) as (1)/(2).  A negative exponent follows the rule a^(-n)=(1)/(a^(n)).<BR>\n" );
document.write( "(1)/(2)\r<BR>\n" );
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document.write( "And the last question:\r<BR>\n" );
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document.write( "2*2^(-1)\r<BR>\n" );
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document.write( "Remove the negative exponent by rewriting 2^(-1) as (1)/(2).  A negative exponent follows the rule a^(-n)=(1)/(a^(n)).<BR>\n" );
document.write( "2*(1)/(2)\r<BR>\n" );
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document.write( "Cancel the common factor of 2 from the first term 2 and the denominator of the second term (1)/(2).<BR>\n" );
document.write( "1*1\r<BR>\n" );
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document.write( "Multiply 1 by 1 to get 1.<BR>\n" );
document.write( "1\r<BR>\n" );
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document.write( " </SPAN>\n" );
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