document.write( "Question 42465: 2 2
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document.write( "(x+y) + (x+3y) - 10(x+3y) - 4(x+y) +29 = 0 , find the value from next expresion\r
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document.write( " 2
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document.write( "2y + xy\r
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document.write( "This problem is not from textbook. \n" );
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Algebra.Com's Answer #27618 by rapaljer(4671)![]() ![]() You can put this solution on YOUR website! \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "This looks like a neat problem. Let's rearrange it and see if this helps sort it out, and subtract 29 from each side while you are at it: \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Notice that you can \"complete the square\" (remember \"half and square\"??) on each of these quantities, by adding 4 on the first blank and 25 on the second blank. \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Since the sum of two squares equals zero, this means that each quantity squared must equal zero!\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "x+y-2=0 and x+3y-5=0\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "x+y=2 \n" ); document.write( "x+3y=5\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Solve by elimination: \n" ); document.write( "-x-y=-2 \n" ); document.write( "x+3y=5\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "So, 2y = 3, \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "x+y=2 \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "NOW, you wanted 2y^2 + xy= \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "R^2 at SCC \n" ); document.write( " |