document.write( "Question 42465: 2 2
\n" ); document.write( "(x+y) + (x+3y) - 10(x+3y) - 4(x+y) +29 = 0 , find the value from next expresion\r
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\n" ); document.write( "2y + xy\r
\n" ); document.write( "\n" ); document.write( "This problem is not from textbook.
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Algebra.Com's Answer #27618 by rapaljer(4671)\"\" \"About 
You can put this solution on YOUR website!
\"%28x%2By%29%5E2+%2B+%28x%2B3y%29%5E2+-+10%28x%2B3y%29+-+4%28x%2By%29+%2B29+=+0\"\r
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\n" ); document.write( "\n" ); document.write( "This looks like a neat problem. Let's rearrange it and see if this helps sort it out, and subtract 29 from each side while you are at it:
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\n" ); document.write( "\n" ); document.write( "Notice that you can \"complete the square\" (remember \"half and square\"??) on each of these quantities, by adding 4 on the first blank and 25 on the second blank.
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\n" ); document.write( "\"%28x%2By%29%5E2+-+4%28x%2By%29+%2B+4+%2B+%28x%2B3y%29%5E2+-10%28x%2B3y%29+%2B+25+=+0\"
\n" ); document.write( "\"++%28x%2By-2%29%5E2++%2B+%28x%2B3y-5%29%5E2+=+0\"\r
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\n" ); document.write( "\n" ); document.write( "Since the sum of two squares equals zero, this means that each quantity squared must equal zero!\r
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\n" ); document.write( "\n" ); document.write( "x+y-2=0 and x+3y-5=0\r
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\n" ); document.write( "\n" ); document.write( "x+y=2
\n" ); document.write( "x+3y=5\r
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\n" ); document.write( "\n" ); document.write( "Solve by elimination:
\n" ); document.write( "-x-y=-2
\n" ); document.write( "x+3y=5\r
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\n" ); document.write( "\n" ); document.write( "So, 2y = 3,
\n" ); document.write( "\"y=3%2F2\"\r
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\n" ); document.write( "\n" ); document.write( "x+y=2
\n" ); document.write( "\"x%2B%283%2F2%29=2\"
\n" ); document.write( "\"x=1%2F2\"\r
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\n" ); document.write( "\n" ); document.write( "NOW, you wanted 2y^2 + xy=\"2%2A%289%2F4%29%2B%281%2F2%29%2A%283%2F2%29=+%2818%2F4%29%2B%283%2F4%29=21%2F4\"\r
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\n" ); document.write( "\n" ); document.write( "R^2 at SCC
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