document.write( "Question 389657: Solve the system of linear equations using the Substitution Method.\r
\n" ); document.write( "\n" ); document.write( "x+3y=2
\n" ); document.write( "-2x-4y=2
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Algebra.Com's Answer #276167 by haileytucki(390)\"\" \"About 
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x+3y=2_-2x-4y=2\r
\n" ); document.write( "\n" ); document.write( "Since 3y does not contain the variable to solve for, move it to the right-hand side of the equation by subtracting 3y from both sides.
\n" ); document.write( "x=-3y+2_-2x-4y=2\r
\n" ); document.write( "\n" ); document.write( "Replace all occurrences of x with the solution found by solving the last equation for x. In this case, the value substituted is -3y+2.
\n" ); document.write( "x=-3y+2_-2(-3y+2)-4y=2\r
\n" ); document.write( "\n" ); document.write( "Multiply -2 by each term inside the parentheses.
\n" ); document.write( "x=-3y+2_6y-4-4y=2\r
\n" ); document.write( "\n" ); document.write( "Since 6y and -4y are like terms, add -4y to 6y to get 2y.
\n" ); document.write( "x=-3y+2_2y-4=2\r
\n" ); document.write( "\n" ); document.write( "Since -4 does not contain the variable to solve for, move it to the right-hand side of the equation by adding 4 to both sides.
\n" ); document.write( "x=-3y+2_2y=4+2\r
\n" ); document.write( "\n" ); document.write( "Add 2 to 4 to get 6.
\n" ); document.write( "x=-3y+2_2y=6\r
\n" ); document.write( "\n" ); document.write( "Divide each term in the equation by 2.
\n" ); document.write( "x=-3y+2_(2y)/(2)=(6)/(2)\r
\n" ); document.write( "\n" ); document.write( "Simplify the left-hand side of the equation by canceling the common factors.
\n" ); document.write( "x=-3y+2_y=(6)/(2)\r
\n" ); document.write( "\n" ); document.write( "Simplify the right-hand side of the equation by simplifying each term.
\n" ); document.write( "x=-3y+2_y=3\r
\n" ); document.write( "\n" ); document.write( "Replace all occurrences of y with the solution found by solving the last equation for y. In this case, the value substituted is 3.
\n" ); document.write( "x=-3(3)+2_y=3\r
\n" ); document.write( "\n" ); document.write( "Multiply -3 by each term inside the parentheses.
\n" ); document.write( "x=-9+2_y=3\r
\n" ); document.write( "\n" ); document.write( "Add 2 to -9 to get -7.
\n" ); document.write( "x=-7_y=3\r
\n" ); document.write( "\n" ); document.write( "This is the solution to the system of equations.
\n" ); document.write( "x=-7_y=3
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