document.write( "Question 389571: 9. Find three consecutive three odd numbers such that 1/7 of the first plus 1/3 of the second plus 1/5 of the third is 63. \n" ); document.write( "

Algebra.Com's Answer #276122 by ewatrrr(24785) $\"\"$ $\"About$

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document.write( "Hi
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document.write( "Let x and (x+2) and (x+4)
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document.write( "represent the first, second and third of three consecutive odd numbers
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document.write( "Question States***
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document.write( " (1/7) x + 1/3(x+2) +1/5(x+4) = 63
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document.write( "solving for x
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document.write( "Multiplying all terms by 105, so as all denominators = 1
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document.write( " 15 + 35(x+2) + 21(x+4) = 63*105
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document.write( "  71x + 154 = 6615
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document.write( "  71x = 6461
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document.write( "     x = 91  Three  consecutive even numbers  are 91,93,95
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document.write( "CHECKING our Answer***
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document.write( " 1/7*91 + 1/3*93 + 1/5*95 = 13 + 31 + 19 = 63 \n" );
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