document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=5356>Question 5356</A>: <I><SPAN STYLE=\"word-break: break-all;\"> I need to solve :\r<BR>\n" );
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document.write( "1/2 + x/3 = 2x/3 - 1/4\r<BR>\n" );
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document.write( "Thanks for your help </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #2761 by </B><A HREF=/tutors/aboutme.mpl?userid=guapa><B>guapa(62)</B></A><img src=\"/images/stars/stars-08.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=guapa><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=2761\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 1/2 +x/3 = (2x)/3 - 1/4<BR>\n" );
document.write( "First you need to find the LCD. In doing it you get rid of all fractions in the equation. In this case the LCD is 12.<BR>\n" );
document.write( "(1*6)/(2*6) + (x*4)/(3*4) = (2x*4)/(3*4)- (1*3)/(4*3)<BR>\n" );
document.write( "6 + 4x = 8x -3<BR>\n" );
document.write( "4x = 9<BR>\n" );
document.write( "x = 9/4 </SPAN>\n" );
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