document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=389460>Question 389460</A>: <I><SPAN STYLE=\"word-break: break-all;\"> I am making a top for a poker table.  The table is an octagon.  The top is also an octagon and has a diameter of 44in and side length of 18 1/2 in.  I am wanting to add an oak trim ring around the top to make it wider.  The trim ring will have a width of 3 in.  I know that each piece will be a trapezoid with the shorter base length being 18 1/2 in and the height being 3 in but I don't know what the new longer base length will be.  In other words i am asking if i add 3 in per side to a 44 in diameter octagon what would the new side lengths be. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #276089 by </B><A HREF=/tutors/aboutme.mpl?userid=Alan3354><B>Alan3354(69443)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Alan3354><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Alan3354><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=276089\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> If the side length = 18.5, the diameter (from flat to flat) = 44.66\"<BR>\n" );
document.write( "If the diameter = 44, the side length = 18.225\"<BR>\n" );
document.write( "That might be more accuracy than you need, since it's probably made of wood.<BR>\n" );
document.write( "Anyway, using 44 for the diameter and 18.225 for the sides:<BR>\n" );
document.write( "Adding 3\" makes the outside side length 20.71 inches.<BR>\n" );
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document.write( "s = (22 + 3)*tan(22.5º)*2<BR>\n" );
document.write( "s =~ 20.71 </SPAN>\n" );
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