document.write( "Question 386816: The perimeter of a rectangle is 40m. If the width is increased by twice the length, the result is 32m. Find the length and width of the rectangle. \n" ); document.write( "
Algebra.Com's Answer #276085 by gwendolyn(128)\"\" \"About 
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Let L be the length of the rectangle
\n" ); document.write( "Let W be the width of the rectangle\r
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\n" ); document.write( "\n" ); document.write( "The perimeter of a rectangle is 40m.
\n" ); document.write( "So:
\n" ); document.write( "2*L + 2*W = 40\r
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\n" ); document.write( "\n" ); document.write( "If the width is increased by twice the length, the result is 32m.
\n" ); document.write( "So:
\n" ); document.write( "W + 2L = 32
\n" ); document.write( "Solve for W by subtracting 2L from both sides:
\n" ); document.write( "W + 2L - 2L = 32 - 2L
\n" ); document.write( "W = 32 - 2L\r
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\n" ); document.write( "\n" ); document.write( "Substitute this value of W back into the first equation:
\n" ); document.write( "2*L + 2*W = 40
\n" ); document.write( "2*L + 2*(32 - 2L) = 40
\n" ); document.write( "Distribute the 2:
\n" ); document.write( "2L + 2*32 - 2*2L = 40
\n" ); document.write( "2L + 64 - 4L = 40
\n" ); document.write( "Collect the L terms:
\n" ); document.write( "-2L + 64 = 40
\n" ); document.write( "Subtract 64 from both sides to isolate the L term:
\n" ); document.write( "-2L + 64 - 64 = 40 - 64
\n" ); document.write( "-2L = -24
\n" ); document.write( "Divide both sides to solve for L
\n" ); document.write( "(-2L)/(-2) = (-24)/(-2)
\n" ); document.write( "L = 12\r
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\n" ); document.write( "\n" ); document.write( "Substituting the value of L into our second equation:
\n" ); document.write( "W = 32 - 2L
\n" ); document.write( "W = 32 - 2*12
\n" ); document.write( "W = 32 - 24
\n" ); document.write( "W = 8
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