document.write( "Question 389518: how to solve (-10,-5) and (-8,-2) with the equation y-y1=m(x-x1) \n" ); document.write( "
Algebra.Com's Answer #276065 by MathTherapy(10858)\"\" \"About 
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how to solve (-10,-5) and (-8,-2) with the equation y-y1=m(x-x1)\r
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\n" ); document.write( "\n" ); document.write( "Obviously, you need to create, not solve an equation in y = mx + b format, using the coordinates (-10, - 5) and (-8, - 2).\r
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\n" ); document.write( "\n" ); document.write( "Find the slope or m: \"%28y%5B2%5D-y%5B1%5D%29%2F%28x%5B2%5D-x%5B1%5D%29\"...... \"%28-2--5%29%2F%28-8--10%29%29\"......\"%28-2%2B5%29%2F%28-8%2B10%29\"......\"3%2F2\"\r
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\n" ); document.write( "\n" ); document.write( "With m, or slope = \"3%2F2\" and one coordinate point (-8, - 2), we can use the point-slope formula to determine the linear equation: \"y+-+y%5B1%5D+=+m%28x+-+x%5B1%5D%29\"__\"y+-+-+2+=+%283%2F2%29%28x+--+8%29\"__\"y+%2B+2+=+%283%2F2%29%28x+%2B+8%29\"__\"y+%2B+2+=+%283%2F2%29x+%2B+12\"__\"highlight_green%28y+=+%283%2F2%29x+%2B+10%29\"
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