document.write( "Question 389485: (3x'3y'2)'2/xy'3\r
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\n" ); document.write( "\n" ); document.write( "Key:
\n" ); document.write( "'=exponent eg: 3x'3 is 3X to the third.
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Algebra.Com's Answer #276050 by haileytucki(390)\"\" \"About 
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((3x^(3)y^(2))^(2))/(xy^(3))\r
\n" ); document.write( "\n" ); document.write( "Expand the exponent (2) to the expression.
\n" ); document.write( "(3^(2)x^(3*2)y^(2*2))/(xy^(3))\r
\n" ); document.write( "\n" ); document.write( "Multiply 3 by 2 to get 6.
\n" ); document.write( "(3^(2)x^(6)y^(2*2))/(xy^(3))\r
\n" ); document.write( "\n" ); document.write( "Multiply 2 by 2 to get 4.
\n" ); document.write( "(3^(2)x^(6)y^(4))/(xy^(3))\r
\n" ); document.write( "\n" ); document.write( "Squaring a number is the same as multiplying the number by itself (3*3). In this case, 3 squared is 9.
\n" ); document.write( "(9x^(6)y^(4))/(xy^(3))\r
\n" ); document.write( "\n" ); document.write( "Reduce the expression (9x^(6)y^(4))/(xy^(3)) by removing a factor of xy^(3) from the numerator and denominator.
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