document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=389487>Question 389487</A>: <I><SPAN STYLE=\"word-break: break-all;\"> perform indicated operation:\r<BR>\n" );
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document.write( "y^2+3y-4/y^2+7y+12 multiplied by 4y^2-36/4y^2-4 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #276048 by </B><A HREF=/tutors/aboutme.mpl?userid=haileytucki><B>haileytucki(390)</B></A><img src=\"/images/stars/stars-10.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=haileytucki><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=haileytucki><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=276048\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> (y^(2)+3y-4)/(y^(2)+7y+12)*(4y^(2)-36)/(4y^(2)-4)\r<BR>\n" );
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document.write( "In this problem 4*-1=-4 and 4-1=3, so insert 4 as the right hand term of one factor and -1 as the right-hand term of the other factor.<BR>\n" );
document.write( "((y+4)(y-1))/(y^(2)+7y+12)*(4y^(2)-36)/(4y^(2)-4)\r<BR>\n" );
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document.write( "In this problem 4*3=12 and 4+3=7, so insert 4 as the right hand term of one factor and 3 as the right-hand term of the other factor.<BR>\n" );
document.write( "((y+4)(y-1))/((y+4)(y+3))*(4y^(2)-36)/(4y^(2)-4)\r<BR>\n" );
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document.write( "Reduce the expression by canceling out the common factor of (y+4) from the numerator and denominator.<BR>\n" );
document.write( "(<X>(y+4)<x>(y-1))/(<X>(y+4)<x>(y+3))*(4y^(2)-36)/(4y^(2)-4)\r<BR>\n" );
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document.write( "Reduce the expression by canceling out the common factor of (y+4) from the numerator and denominator.<BR>\n" );
document.write( "(y-1)/(y+3)*(4y^(2)-36)/(4y^(2)-4)\r<BR>\n" );
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document.write( "Factor out the GCF of 4 from each term in the polynomial.<BR>\n" );
document.write( "(y-1)/(y+3)*(4(y^(2))+4(-9))/(4y^(2)-4)\r<BR>\n" );
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document.write( "Factor out the GCF of 4 from 4y^(2)-36.<BR>\n" );
document.write( "(y-1)/(y+3)*(4(y^(2)-9))/(4y^(2)-4)\r<BR>\n" );
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document.write( "The binomial can be factored using the difference of squares formula, because both terms are perfect squares.  The difference of squares formula is a^(2)-b^(2)=(a-b)(a+b).<BR>\n" );
document.write( "(y-1)/(y+3)*(4(y-3)(y+3))/(4y^(2)-4)\r<BR>\n" );
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document.write( "Factor out the GCF of 4 from each term in the polynomial.<BR>\n" );
document.write( "(y-1)/(y+3)*(4(y-3)(y+3))/(4(y^(2))+4(-1))\r<BR>\n" );
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document.write( "Factor out the GCF of 4 from 4y^(2)-4.<BR>\n" );
document.write( "(y-1)/(y+3)*(4(y-3)(y+3))/(4(y^(2)-1))\r<BR>\n" );
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document.write( "The binomial can be factored using the difference of squares formula, because both terms are perfect squares.  The difference of squares formula is a^(2)-b^(2)=(a-b)(a+b).<BR>\n" );
document.write( "(y-1)/(y+3)*(4(y-3)(y+3))/(4(y-1)(y+1))\r<BR>\n" );
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document.write( "Reduce the expression (4(y-3)(y+3))/(4(y-1)(y+1)) by removing a factor of 4 from the numerator and denominator.<BR>\n" );
document.write( "(y-1)/(y+3)*((y-3)(y+3))/((y-1)(y+1))\r<BR>\n" );
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document.write( "Cancel the common factor of (y+3) from the denominator of the first expression and the numerator of the second expression.<BR>\n" );
document.write( "(y-1)*(y-3)/((y-1)(y+1))\r<BR>\n" );
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document.write( "Reduce the expression by canceling out the common factor of (y-1) from the numerator and denominator.<BR>\n" );
document.write( "(y-3))/(y+1)\r<BR>\n" );
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document.write( "Reduce the expression by canceling out the common factor of (y-1) from the numerator and denominator.<BR>\n" );
document.write( "(y-3)/(y+1) </SPAN>\n" );
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