document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=389529>Question 389529</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Can you please help me on this question....\r<BR>\n" );
document.write( "\n" );
document.write( "|-2x - 4| < 12\r<BR>\n" );
document.write( "\n" );
document.write( "If x represents positive amounts in kilograms, what is the solution set?\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "Only positive integer solutions to the equation can be used and accepted.<BR>\n" );
document.write( "How does this change the answer to the first question? Explain. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #276026 by </B><A HREF=/tutors/aboutme.mpl?userid=haileytucki><B>haileytucki(390)</B></A><img src=\"/images/stars/stars-10.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=haileytucki><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=haileytucki><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=276026\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> See if this helps you out a little\r<BR>\n" );
document.write( "\n" );
document.write( "|-2x-4|<12\r<BR>\n" );
document.write( "\n" );
document.write( "Remove the absolute value term.  This creates a \ on the right-hand side of the equation because |x|=\x.<BR>\n" );
document.write( "-2x-4<\(12)\r<BR>\n" );
document.write( "\n" );
document.write( "Set up the + portion of the \ solution.<BR>\n" );
document.write( "-2x-4<12\r<BR>\n" );
document.write( "\n" );
document.write( "Move all terms not containing x to the right-hand side of the inequality.<BR>\n" );
document.write( "-2x<16\r<BR>\n" );
document.write( "\n" );
document.write( "Divide each term in the inequality by -2.<BR>\n" );
document.write( "x>-8\r<BR>\n" );
document.write( "\n" );
document.write( "Set up the - portion of the \ solution.  When solving the - portion of an inequality, flip the direction of the inequality sign.<BR>\n" );
document.write( "-2x-4>-(12)\r<BR>\n" );
document.write( "\n" );
document.write( "Multiply -1 by the 12 inside the parentheses.<BR>\n" );
document.write( "-2x-4>-12\r<BR>\n" );
document.write( "\n" );
document.write( "Since -4 does not contain the variable to solve for, move it to the right-hand side of the inequality by adding 4 to both sides.<BR>\n" );
document.write( "-2x>4-12\r<BR>\n" );
document.write( "\n" );
document.write( "Subtract 12 from 4 to get -8.<BR>\n" );
document.write( "-2x>-8\r<BR>\n" );
document.write( "\n" );
document.write( "Divide each term in the inequality by -2.<BR>\n" );
document.write( "-(2x)/(-2)<-(8)/(-2)\r<BR>\n" );
document.write( "\n" );
document.write( "Simplify the left-hand side of the inequality by canceling the common factors.<BR>\n" );
document.write( "x<-(8)/(-2)\r<BR>\n" );
document.write( "\n" );
document.write( "Simplify the right-hand side of the inequality by simplifying each term.<BR>\n" );
document.write( "x<4\r<BR>\n" );
document.write( "\n" );
document.write( "The solution to the inequality includes both the positive and negative versions of the absolute value.<BR>\n" );
document.write( "x>-8 and x<4\r<BR>\n" );
document.write( "\n" );
document.write( "The solution is the set of values where x>-8 and x<4.<BR>\n" );
document.write( "-8<x<4 </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );