document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=389491>Question 389491</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The denominator of the fraction is 2 more than the numerator. If 1 is subtracted from both numerator and denominator, the resulting fraction has a value of 1/2. Find the original fraction. (Need a complete solution for this. Thanks) </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #276007 by </B><A HREF=/tutors/aboutme.mpl?userid=ptaylor><B>ptaylor(2198)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ptaylor><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ptaylor><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=276007\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let x=numerator<BR>\n" );
document.write( "Then x+2=denominator<BR>\n" );
document.write( "So our equation to solve is:<BR>\n" );
document.write( "(x-1)/(x+2-1)=1/2 simplifying we have<BR>\n" );
document.write( "(x-1)/(x+1)=1/2  now multiply each side by 2(x+1)<BR>\n" );
document.write( "2(x-1)=x+1<BR>\n" );
document.write( "2x-2=x+1 subtract x from and add 2 to each side:<BR>\n" );
document.write( "2x-x-2+2=x-x+1+2 collect like terms<BR>\n" );
document.write( "x=3<BR>\n" );
document.write( "CK<BR>\n" );
document.write( "(3-1)/(3+1)=1/2<BR>\n" );
document.write( "2/4=1/2<BR>\n" );
document.write( "1/2=1/2\r<BR>\n" );
document.write( "\n" );
document.write( "Hope this helps---ptaylor<BR>\n" );
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