document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=389475>Question 389475</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Please help me solve this question.\r<BR>\n" );
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document.write( " If 2% of the auto tires manufactured by a company <BR>\n" );
document.write( "are defective and 2 tires are randomly selected from an entire week’s production, find the probability <BR>\n" );
document.write( "that neither is defective (state your probability as a decimal carried out to the fourth place). <BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #276000 by </B><A HREF=/tutors/aboutme.mpl?userid=gwendolyn><B>gwendolyn(128)</B></A><img src=\"/images/stars/stars-09.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=gwendolyn><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=gwendolyn><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=276000\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> P(the first tire is NOT defective) is the same as 100% - P(the first tire IS defective):<BR>\n" );
document.write( "100% - 2% = 98% or (0.98)\r<BR>\n" );
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document.write( "P(the second tire is NOT defective) is the same: 98% (or 0.98).\r<BR>\n" );
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document.write( "We need both these events to happen, so we multiply the probabilities together:\r<BR>\n" );
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document.write( ".98 * .98 = .9604\r<BR>\n" );
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