document.write( "Question 795: I need help on a proprtion, \r
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document.write( "2u-3/4u=u-1/u I did cross product method on this one and i got\r
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document.write( "2u(squared)-3u= 4u (squared)-4u then i isolated the u and the u (squared) and came out with u=2u(squared). I think i did this all right, but i'm not sure what the u would be. I missed this lesson in math becuase i'm on homebound school because of an illness i have. If you can please help me out i would appreciate it. Thank You. \n" );
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Algebra.Com's Answer #276 by pushpaharan(47)![]() ![]() ![]() You can put this solution on YOUR website! 2u-3/4u=u-1/u \n" ); document.write( "2u-u = 1/u+3/4u \n" ); document.write( "u= 7/4u \n" ); document.write( "u^2 = 7/4 \n" ); document.write( "u= Sqrt(7/4) = 1.32 \n" ); document.write( " |