document.write( "Question 795: I need help on a proprtion, \r
\n" ); document.write( "\n" ); document.write( "2u-3/4u=u-1/u I did cross product method on this one and i got\r
\n" ); document.write( "\n" ); document.write( "2u(squared)-3u= 4u (squared)-4u then i isolated the u and the u (squared) and came out with u=2u(squared). I think i did this all right, but i'm not sure what the u would be. I missed this lesson in math becuase i'm on homebound school because of an illness i have. If you can please help me out i would appreciate it. Thank You.
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Algebra.Com's Answer #276 by pushpaharan(47)\"\" \"About 
You can put this solution on YOUR website!
2u-3/4u=u-1/u
\n" ); document.write( "2u-u = 1/u+3/4u
\n" ); document.write( "u= 7/4u
\n" ); document.write( "u^2 = 7/4
\n" ); document.write( "u= Sqrt(7/4) = 1.32
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