document.write( "Question 389385: Man'S AGE IS 3TIMES OF HIS SON .TEN YEARS AGO HE WAS 5TIMES OF HIS SON .FIND AGES OF MAN AND SON.USING SIMULTANEOUS EQUATIONS TO SOLVE IT . ANS 20YEARS 60YEARS. \n" ); document.write( "
Algebra.Com's Answer #275919 by dudeantariksh(10)\"\" \"About 
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hi there!!
\n" ); document.write( "well, in order to solve ur problem we'll go by the track of 'LINEAR EQUATIONS IN TWO VARABLES' or 'simulataneous equations'
\n" ); document.write( "Thereby, let us assume that man's present age is x years and that of his son is y years.
\n" ); document.write( "now , as per the first given condition that' Man'S AGE IS 3TIMES his son's',
\n" ); document.write( "we get,
\n" ); document.write( " x = 3y
\n" ); document.write( "now we subtrat [3y] from both sides and get
\n" ); document.write( " x-3y = 0.............................. result no.1
\n" ); document.write( "now,
\n" ); document.write( "man's age 10 years ago was (x-10) years and that of his son will be(y-10)years.
\n" ); document.write( "now, as per the second given condition that' TEN YEARS AGO HE WAS 5TIMES OF HIS SON', we get,
\n" ); document.write( " (x-10)= 5(y-10)
\n" ); document.write( " thus, x-10 = 5y - 50
\n" ); document.write( "now we take the like terms al on one side, i.e., we take the variables[alphabets] on 1 side and the contants[numbers] on one side.
\n" ); document.write( "we get x-5y = -50+10
\n" ); document.write( " x-5y = -40............................result no.2
\n" ); document.write( "now we subtract equation 2 from 1 and we get,
\n" ); document.write( "(x-3y)-(x-5y)= 0-(-40)
\n" ); document.write( "now, as we have the minus sign outside d bracket in d L.HS., all the terms under it change their signs.
\n" ); document.write( "thus,
\n" ); document.write( "x - 3y -x +5y = 40/highlight x
\n" ); document.write( "thus, x nd -x get cancelled.
\n" ); document.write( "thus,
\n" ); document.write( "5y-3y = 40
\n" ); document.write( "thus,
\n" ); document.write( " 2y = 40
\n" ); document.write( "now we divide by 2 throughout
\n" ); document.write( "and we get.(y = 20).................................result no.3/highlight y=20
\n" ); document.write( "now we substitute the value of y in equation 1 for obtaining x and we get,\r
\n" ); document.write( "\n" ); document.write( "x-3(20) = 0
\n" ); document.write( "therefore,
\n" ); document.write( "x-60 +0
\n" ); document.write( "therefore, (x=60)/highlight x=60
\n" ); document.write( "now, x = 60 years
\n" ); document.write( "and y = 20 years.
\n" ); document.write( "thus,
\n" ); document.write( "we find that the present age of father is 60 years and that of his sone is 20 years..
\n" ); document.write( "[since, the given values and obtained values are the same there is n need for verification]
\n" ); document.write( " \n" ); document.write( "
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