document.write( "Question 389378: a rectangle has a length one foot longer than twice the width. the area of the rectangle is 253 square feet. find the (a) length and (b) width.\r
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document.write( "can you show me how to do this problem? thanks. \n" );
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Algebra.Com's Answer #275916 by mananth(16946)![]() ![]() You can put this solution on YOUR website! a rectangle has a length one foot longer than twice the width. the area of the rectangle is 253 square feet. find the (a) length and (b) width. \n" ); document.write( ".. \n" ); document.write( "the unknowns are the length & width. \n" ); document.write( "but they have a relation. \n" ); document.write( "let width be x feet \n" ); document.write( "length will be 2x+1 \n" ); document.write( ".. \n" ); document.write( "L*W=Area \n" ); document.write( "x(2x+1)= Area \n" ); document.write( "x(2x+1)= 253 \n" ); document.write( "2x^2+2x= 253 \n" ); document.write( "-253 \n" ); document.write( "2x^2+2x-253=0 \n" ); document.write( "solve for roots using quadratic equation. \n" ); document.write( "a=2,b=2,c-253 \n" ); document.write( "b^2-4ac=2028 \n" ); document.write( " \n" ); document.write( "width = 10.758 feet \n" ); document.write( " \n" ); document.write( "This is negative so it is not practical \n" ); document.write( ".. \n" ); document.write( "width = 10.76 \n" ); document.write( "length = (2x+10 \n" ); document.write( "Length = 2*(10.76+1) \n" ); document.write( "Length = 23.52 feet \n" ); document.write( "... \n" ); document.write( "CHECK \n" ); document.write( "23.52*10.76=253.07 \n" ); document.write( "... \n" ); document.write( "m.ananth@hotmail.ca \n" ); document.write( " |