document.write( "Question 389378: a rectangle has a length one foot longer than twice the width. the area of the rectangle is 253 square feet. find the (a) length and (b) width.\r
\n" ); document.write( "\n" ); document.write( "can you show me how to do this problem? thanks.
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Algebra.Com's Answer #275916 by mananth(16946)\"\" \"About 
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a rectangle has a length one foot longer than twice the width. the area of the rectangle is 253 square feet. find the (a) length and (b) width.
\n" ); document.write( "..
\n" ); document.write( "the unknowns are the length & width.
\n" ); document.write( "but they have a relation.
\n" ); document.write( "let width be x feet
\n" ); document.write( "length will be 2x+1
\n" ); document.write( "..
\n" ); document.write( "L*W=Area
\n" ); document.write( "x(2x+1)= Area
\n" ); document.write( "x(2x+1)= 253
\n" ); document.write( "2x^2+2x= 253
\n" ); document.write( "-253
\n" ); document.write( "2x^2+2x-253=0
\n" ); document.write( "solve for roots using quadratic equation.
\n" ); document.write( "a=2,b=2,c-253
\n" ); document.write( "b^2-4ac=2028
\n" ); document.write( "\"x1=%28-2%2Bsqrt%282028%29%29%2F%282%2A2%29\"
\n" ); document.write( "width = 10.758 feet
\n" ); document.write( "\"x2=%28-2-sqrt%282028%29%29%2F%282%2A2%29\"
\n" ); document.write( "This is negative so it is not practical
\n" ); document.write( "..
\n" ); document.write( "width = 10.76
\n" ); document.write( "length = (2x+10
\n" ); document.write( "Length = 2*(10.76+1)
\n" ); document.write( "Length = 23.52 feet
\n" ); document.write( "...
\n" ); document.write( "CHECK
\n" ); document.write( "23.52*10.76=253.07
\n" ); document.write( "...
\n" ); document.write( "m.ananth@hotmail.ca
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