document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=384450>Question 384450</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A chemist has  a 45% mixture of hydrochloric acid and 80% mixture of the same acid. How Much of each should be mixed together to get 60ml of a 60% solution of hydrochloric acid?? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #275854 by </B><A HREF=/tutors/aboutme.mpl?userid=lwsshak3><B>lwsshak3(11628)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=lwsshak3><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=275854\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> let x = the amount (ml) of 45% mixture should be mixed with the 80% solution<BR>\n" );
document.write( "then 60-x =  the amount (ml) of 80% mixture should be mixed with the 45% solution<BR>\n" );
document.write( "mixing these  two amounts together will give 60 ml of a 60% solution.\r<BR>\n" );
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document.write( ",45x+.8(60-x) =.6(60)<BR>\n" );
document.write( ".45x +48-.8x =36<BR>\n" );
document.write( ".35x = 12x <BR>\n" );
document.write( "x =12/.35 =34.29 ml<BR>\n" );
document.write( "60-x =25.71 ml\r<BR>\n" );
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document.write( "ans: 34.29 ml of the 45% mixture should be mixed with 25.71 ml of  the 80% mixture to get 60 ml of a 60% solution of hydrochloric acid </SPAN>\n" );
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