document.write( "Question 389296: On Monday, Carlos drove to work in 35 minutes. On Tuesday, he averaged 9 miles per hour more and arrived 7 minutes faster. How far (in miles) does Carlos travel from home to work? \n" ); document.write( "
Algebra.Com's Answer #275836 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! On Monday, Carlos drove to work in 35 minutes. \n" ); document.write( " On Tuesday, he averaged 9 miles per hour more and arrived 7 minutes faster. \n" ); document.write( " How far (in miles) does Carlos travel from home to work? \n" ); document.write( ": \n" ); document.write( "Let d = distance traveled to work \n" ); document.write( "Let s = average speed on monday \n" ); document.write( "then \n" ); document.write( "(s+9) = average speed on tuesday \n" ); document.write( ": \n" ); document.write( "Write two time equations: time = dist/speed \n" ); document.write( " \n" ); document.write( "Cross multiply \n" ); document.write( "60d = 35s \n" ); document.write( "Simplify, divide by 5 \n" ); document.write( "12d = 7s \n" ); document.write( "12d - 7s = 0 \n" ); document.write( "and \n" ); document.write( " \n" ); document.write( "Cross multiply \n" ); document.write( "60d = 28(s+9) \n" ); document.write( "60d = 28s + 252 \n" ); document.write( "Simplify, divide by 4 \n" ); document.write( "15d = 7s + 63 \n" ); document.write( "15d - 7s = 63 \n" ); document.write( ": \n" ); document.write( "Subtract the 12d - 7s = 0 from the above equation \n" ); document.write( "15d - 7s = 63 \n" ); document.write( "12d - 7s = 0 \n" ); document.write( "----------------subtraction eliminates s, find d \n" ); document.write( "3d = 63 \n" ); document.write( "d = \n" ); document.write( "d = 21 miles is C's distance to work \n" ); document.write( ": \n" ); document.write( ": \n" ); document.write( "Check this: find the the speed \n" ); document.write( "7s = 12(21) \n" ); document.write( "7s = 252 \n" ); document.write( "s = 252/7 \n" ); document.write( "s = 36 mph \n" ); document.write( ": \n" ); document.write( "Find the times \n" ); document.write( "21/36 = .583 hrs \n" ); document.write( "21/45 = .467 hrs; (9 mph faster) \n" ); document.write( "----------------- \n" ); document.write( "difer = .116 hrs which is about 7 min \n" ); document.write( " \n" ); document.write( " |