document.write( "Question 389281: Let the function f be defined by the equation y = f(x), where x and f(x) are real numbers. Find the domain of the function.\r
\n" ); document.write( "\n" ); document.write( "f(x)= sqrt of x^2-64\r
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\n" ); document.write( "\n" ); document.write( "(the sqrt is of the x^2-64 not just the x^2)
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Algebra.Com's Answer #275825 by richard1234(7193)\"\" \"About 
You can put this solution on YOUR website!
We have\r
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\n" ); document.write( "\n" ); document.write( "\"f%28x%29+=+sqrt%28x%5E2+-+64%29\"\r
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\n" ); document.write( "\n" ); document.write( "For the function to be defined on the real numbers, the square root expression must be nonnegative. Therefore,\r
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\n" ); document.write( "\n" ); document.write( "\"x%5E2+-+64+%3E=+0\"\r
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\n" ); document.write( "\n" ); document.write( "\"x%5E2+%3E=+64\"\r
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\n" ); document.write( "\n" ); document.write( "\"x+%3E=+8\" or \"x+%3C=+-8\"
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