document.write( "Question 389139: Lateral area and surface area of a regular square pyramid with base edge length 12 and the altitude of the pyramid is 8 \n" ); document.write( "

Algebra.Com's Answer #275801 by ewatrrr(24785) $\"\"$ $\"About$

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document.write( "Hi,         
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document.write( "'regular square pyramid' with base edge length 12 and the altitude of 8
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document.write( "surface area = base area + area of the 4 faces(lateral area)
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document.write( "Area of trangular face = (1/2)b*slant height
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document.write( "Picture drawing an altitude from the apex to the base, forming right triangle
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document.write( "using the Pythagoream Theorem c^2 = a^2 = b^2 where c is the slant height
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document.write( "slant height for this 'square pyaramid' = 
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document.write( "lateral area = 4 [(1/2)12*10) = 2*120 = 240
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document.write( "surface area =  base area + 180 = 12*12 + 240 = 144 + 240 = 384 \n" );
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