document.write( "Question 389243: hello,
\n" ); document.write( "I really need help in solving these two equations. The question is as following:\r
\n" ); document.write( "\n" ); document.write( "write the following as a single power, then evaluate.
\n" ); document.write( "(-32)^3/5 x (-32)^4/5 / (-32)^2/5\r
\n" ); document.write( "\n" ); document.write( "and\r
\n" ); document.write( "\n" ); document.write( "4096^3/4 / 4096^2/3 x 4096^5/6\r
\n" ); document.write( "\n" ); document.write( "thanking you in advance! \n" ); document.write( "

Algebra.Com's Answer #275797 by stanbon(75887) $\"\"$ $\"About$

You can put this solution on YOUR website!
write the following as a single power, then evaluate.
\n" ); document.write( "(-32)^3/5 x (-32)^4/5 / (-32)^2/5
\n" ); document.write( "---
\n" ); document.write( "= (-32)^[3/5 + 4/5 - 2/5]
\n" ); document.write( "---
\n" ); document.write( "= (-32)^[5/5]
\n" ); document.write( "--
\n" ); document.write( "= -32
\n" ); document.write( "==================================
\n" ); document.write( "and
\n" ); document.write( "4096^3/4 / 4096^2/3 x 4096^5/6
\n" ); document.write( "---
\n" ); document.write( "= 4096^[3/4 + 2/3 + 5/6]
\n" ); document.write( "---
\n" ); document.write( "= 4096^[(9+8+10)/12]
\n" ); document.write( "---
\n" ); document.write( "= 4096^(27/12)
\n" ); document.write( "---
\n" ); document.write( "= 2^27
\n" ); document.write( "---
\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
\n" ); document.write( " \n" ); document.write( "

\n" );