document.write( "Question 389251: one x-intercept of a parabola is at a point of (1,0)use the factor method to find the other x-intercept defined by this equation: y=-5x^2+15x-10. \n" ); document.write( "

Algebra.Com's Answer #275793 by ewatrrr(24785) $\"\"$ $\"About$

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document.write( "Hi
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document.write( "y=-5x^2+15x-10
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document.write( "Factoring to find the x-intercepts when y = 0
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document.write( " -5x^2 + 15x  - 10 = 0
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document.write( " -5(x^2 - 3x + 2) = 0
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document.write( " -5(x-2)(x-1)=0 Note:SUM of the inner product(-2x) and the outer product(-x) = -  (x-1)=0 
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document.write( "    x = 1  As the question states and...
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document.write( "  (x-2)=0
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document.write( "    x = 2
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document.write( "Please note vertex (3/2, 5/4 )
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document.write( "found by completing square for y = -5x^2+15x-10 = -5(x-3/2)^2 + 5/4)
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document.write( "the vertex form of a parabola,  where(h,k) is the vertex
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