document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=389252>Question 389252</A>: <I><SPAN STYLE=\"word-break: break-all;\"> An alloy of tin is 15% tin and weighs 20 pounds. A second alloy is 10% tin. How many pounds of the second alloy must be added to the first to<BR>\n" );
document.write( " get a 12% mixture?  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #275789 by </B><A HREF=/tutors/aboutme.mpl?userid=CharlesG2><B>CharlesG2(834)</B></A><img src=\"/images/stars/stars-11.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=CharlesG2><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=275789\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> An alloy of tin is 15% tin and weighs 20 pounds. A second alloy is 10% tin. How many pounds of the second alloy must be added to the first to<BR>\n" );
document.write( " get a 12% mixture? \r<BR>\n" );
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document.write( "%A * amount A + %B * amount B = %C * amount C<BR>\n" );
document.write( "15% * 20 + 10% * B = 12% * (20 + B)<BR>\n" );
document.write( "0.15 * 20 + 0.1 * B = 0.12 * (20 + B)<BR>\n" );
document.write( "3 + 0.1B = 2.4 + 0.12B<BR>\n" );
document.write( "0.6 = 0.12B - 0.1B<BR>\n" );
document.write( "0.6 = 0.02B<BR>\n" );
document.write( "B = 30<BR>\n" );
document.write( "30 pounds of the second alloy to get 50 pounds of 12% tin<BR>\n" );
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