document.write( "Question 389197: Steven left Town A and walked towards Town B at a speed of 100m/min. At the same time, Jason and Melvin started from Town B and walked towards Town A at a speed of 80m/min and 75m/min respectively. If Steven met Melvin six minutes after passing Jason, find the distance between Town A and Town B. \n" ); document.write( "
Algebra.Com's Answer #275736 by mananth(16946)\"\" \"About 
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Steven left Town A and walked towards Town B at a speed of 100m/min. At the same time, Jason and Melvin started from Town B and walked towards Town A at a speed of 80m/min and 75m/min respectively. If Steven met Melvin six minutes after passing Jason, find the distance between Town A and Town B.
\n" ); document.write( "...
\n" ); document.write( "Steven ----- 100m/min
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\n" ); document.write( "Jason--------80m/min
\n" ); document.write( "...
\n" ); document.write( "Melvin-------75m/min
\n" ); document.write( "......
\n" ); document.write( "Let distance between towns be x m\r
\n" ); document.write( "\n" ); document.write( "Steven ----- 100m/min
\n" ); document.write( "Jason--------80m/min
\n" ); document.write( "combined speed = 180 m.min
\n" ); document.write( "Time taken = x/180 minutes.
\n" ); document.write( "...\r
\n" ); document.write( "\n" ); document.write( "Steven ----- 100m/min
\n" ); document.write( "Melvin-------75m/min
\n" ); document.write( "combine speed = 175 m/min
\n" ); document.write( "..
\n" ); document.write( "Time = x/175
\n" ); document.write( "...
\n" ); document.write( "Difference in time of meeting = 6 minutes.
\n" ); document.write( "x/175 - x/180 = 6
\n" ); document.write( "(180x-175x)/175*180=6
\n" ); document.write( "5x=175*180*6
\n" ); document.write( "5x=189,000
\n" ); document.write( "/5
\n" ); document.write( "x= 37,800 meters
\n" ); document.write( "OR 37.8 km
\n" ); document.write( "...
\n" ); document.write( "m.ananth@hotmail.ca\r
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