document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=388149>Question 388149</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Draw a circle with a diameter of 7 cm and a point,P, 10cm from the centre of this circle. Complete the diagram by adding the two tangents to the circle from the point P. Label the points of the tangency A and B) Provide sufficient additional information to determine the lengths of PA and PB. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #275716 by </B><A HREF=/tutors/aboutme.mpl?userid=robertb><B>robertb(5830)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=robertb><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=robertb><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=275716\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=drawing%28400%2C400%2C-8%2C11%2C-9.5%2C9.5%2C+%0D%0A%0D%0Acircle%280%2C0%2C3.5%29%2C+locate%28-0.4%2C0%2CO%29%2Clocate%2810%2C0%2CP%29%2C+locate%281%2C4%2CA%29%2C%0D%0Aline%280%2C0%2C10%2C0%29%2C+line%2810%2C0%2C+-12%2C8%29%2C+line%2810%2C0%2C+-12%2C-8.2%29%2C%0D%0Aline%280%2C0%2C0.9%2C3.3%29%2C+locate%281%2C-3.5%2CB%29%2C+line%280%2C0%2C0.9%2C-3.3%29%0D%0Alocate%284.5%2C0%2C10%29+%2C+locate%280.8%2C+2%2C+3.5%29%2C+locate%280.8%2C-1.5%2C+3.5%29%2Clocate%285%2C+0%2C+10%29%0D%0A+%29 ALIGN=MIDDLE   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "Diameter = 7 cm-----> radius = 7/2 cm. The angles at the points of tangency are both right angles, so we can apply the Pythagorean Theorem with OP as the hypotenuse:<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=PA+=+PB+=+sqrt%2810%5E2-+%287%2F2%29%5E2%29+=+sqrt%28100+-+49%2F4%29+=+sqrt%28351%2F4%29+=+3sqrt%2839%29%2F2 ALIGN=MIDDLE   DISABLED_style= \"max-width:90%; height:auto;\" > cm. </SPAN>\n" );
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